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Home / Technology / Delicious Sony Xperia XZ3 image reveals unchanged design from XZ2 Premium-Technology News, Firstpost

Delicious Sony Xperia XZ3 image reveals unchanged design from XZ2 Premium-Technology News, Firstpost



After launching Xperia XZ2 last year and Xperia XZ2 Premium earlier this year, the rumors of Sony will release Xperia XZ3 for speed. A new leak now seems to show how the XZ3 is expected to look.

  Sony Xperia XZ2 Premium. Picture: Sony UK

Sony Xperia XZ2 Premium. Sony: Sony 19659004. Unlike most other popular smartphone brands, Sony has no intention of hitting any of their smartphones and as far as XZ3 go pictures are taken, Sony does not seem like that very much. Instead, we have a design that is almost identical to XZ3 Premium released earlier this year. The only difference here is that the XZ2 Premium had a dual camera layout on the backside while the XZ3 has only one.

According to a report of MySmartprice First to get hold of the leaked image, Sony may plan to throw a massive 48 MP camera into the mix and therefore look We only have a single camera frame on the back. There is also a fingerprint scanner on the back of the phone that sits further down the center of the phone.

  Sony Xperia XZ3 leaked reproduction. Image: MySmartprice

Sony Xperia XZ3 leaked reproduction. Picture: MySmartprice

When you look at the backside, there is an additional sensor between the primary camera and dual-tone LED flash. This may indicate that Sony can use its hybrid focusing technology that combines phase detection and laser assisted autofocus.

Overall, Sony is not tinkering around the design a lot this year, but when it comes to internals, we should expect the top of the Qualcomm Snapdragon 845 processor and QHD + display line. The phone is also expected to run Android Pie out of the box.

Now Sony has not published anything about the phone yet, but the company is expected to start the phone very soon at IFA Berlin, starting 31 August. [!19659011] the function (f, b, e, v, n, t, r) {if (f.fbq) returns; n = f.fbq = function () {n.callMethod?
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